(b) Here, $c = c,\ m = 2,\ a^{2} = 16$ $\because\ \ \ c^{2} = a^{2}\left( 1 + m^{2} \right)\ \ \therefore\ \ \ c^{2} = 16(1 + 4)$ $\Rightarrow \ \ \ c^{2} = 80$
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Ph.D. in Physics with 19+ years of teaching experience.