(c)
Here $\sin^{2}\beta = 3\sin^{2}\theta$ (i)
By the question, $\cos^{2}\theta + \cos^{2}\theta + \cos^{2}\beta = 1$ (ii)
$\Rightarrow \ \cos^{2}\beta = 1 - 2\cos^{2}\theta$ (iii)
Adding (i) and (iii), we get
$1 = 1 + 3\sin^{2}\theta - 2\cos^{2}\theta$
$\Rightarrow 1 = 1 + 3\left( 1 - \cos^{2}\theta \right) - 2\cos^{2}\theta$
$\Rightarrow 5\cos^{2}\theta = 3$
$\Rightarrow \cos^{2}\theta = \frac{3}{5}$