Q. The value of ${\lim_{x \rightarrow 0}\left( \frac{1 + 5x^{2}}{1 + 3x^{2}} \right)}^{1/x^{2}}$ is

A) $e^{2}$
B) $e$
C) $\frac{1}{e}$
D) $\frac{1}{e^{2}}$
Explanation

(a)
${\lim_{x \rightarrow 0}\left( \frac{1 + 5x^{2}}{1 + 3x^{2}} \right)}^{1/x^{2}} = {\lim_{x \rightarrow 0}\left( 1 + \frac{2x^{2}}{1 + 3x^{2}} \right)}^{1/x^{2}}$
$= e^{\lim_{x \rightarrow 0}{\frac{1}{x^{2}}\left( \frac{2x^{2}}{1 + 3x^{2}} \right)}} = e^{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.