Q. $\lim_{x \rightarrow \infty}\left( \frac{x + 2}{x + 1} \right)^{x + 3}$ is
A) 1
B) $e$
C) $e^{2}$
D) $e^{3}$
Explanation
(b)
$\lim_{x \rightarrow \infty}\left( 1 + \frac{1}{x + 1} \right)^{x + 3}$
$= e^{\lim_{x \rightarrow \infty}\frac{x + 3}{x + 1}} = e$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.