If $f(1) = 2$ and $f^{'}(1) = 1$, then value of $\lim_{x \rightarrow 1}\frac{2x - f(x)}{x - 1}$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$\lim_{x \rightarrow 1}\frac{2x - f(x)}{x - 1}$
$= \lim_{x \rightarrow 1}\frac{2 - f'(x)}{1}$ (by L’ Hospital’s rule)
$= 2 - f^{'}(1)$
$= 2 - (1) = 1$

Q. If $f(1) = 2$ and $f^{'}(1) = 1$, then value of $\lim_{x \rightarrow 1}\frac{2x - f(x)}{x - 1}$ is

Explanation

Reviewed by Dr. Abubacker

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