Q. $\lim_{x \rightarrow 1}\frac{x^{8} - 2x + 1}{x^{4} - 2x + 1}$ equals
A) 3
B) 0
C) -3
D) 1
Explanation
(a)
$\lim_{x \rightarrow 1}\frac{x^{8} - 2x + 1}{x^{4} - 2x + 1} = \lim_{x \rightarrow 1}\frac{8x^{7} - 2}{4x^{3} - 2}$
$= \frac{8 - 2}{4 - 2} = 3$ [using L’ Hospital’s rule]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.