(b) LHL$= \lim_{x \rightarrow 0^{-}}{f(x)} = \lim_{h \rightarrow 0}{f(0 - h)} = 1$ [$\because(0 - h)$ is rational] RHL$= \lim_{x \rightarrow 0^{+}}{f(x)} = \lim_{h \rightarrow 0}{f(0 + h)} = 1$ [$\because(0 + h)$ is rational] Hence, LHL=RHL=1
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