Q. $\lim_{x \rightarrow 0}x^{2}\sin\frac{\pi}{x}$ is equal to
A) 1
B) 0
C) Does not exist
D) $\infty$
Explanation
(b)
$\lim_{x \rightarrow 0}x^{2}\sin\left( \frac{\pi}{x} \right) = \lim_{x \rightarrow 0}{\pi x}.\frac{\sin\frac{\pi}{x}}{\frac{\pi}{x}} = 0(1) = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.