Q. $\lim_{x \rightarrow 0}\frac{2\sin^{2}{3x}}{x^{2}}$ is equal to
A) 0
B) 1
C) 18
D) 36
Explanation
(c)
$\lim_{x \rightarrow 0}\frac{2\sin^{2}{3x}}{x^{2}} = \lim_{x \rightarrow 0}{2\left( \frac{\sin{3x}}{3x} \right)^{2} \times \frac{9}{1} = 18}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.