$\lim_{x \rightarrow 1}\frac{2x^{2} + x - 3}{3x^{3} - 3x^{2} + 2x - 2}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(a)
$\lim_{x \rightarrow 1}\frac{2x^{2} + x - 3}{3x^{3} - 3x^{2} + 2x - 2} = \lim_{x \rightarrow 1}\frac{(2x + 3)(x - 1)}{\left( 3x^{2} + 2 \right)(x - 1)}$
$= \lim_{x \rightarrow 1}{\frac{2x + 3}{3x^{2} + 2} = 1}$

Q. $\lim_{x \rightarrow 1}\frac{2x^{2} + x - 3}{3x^{3} - 3x^{2} + 2x - 2}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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