(a)
Given, $\lim_{x \rightarrow 0}{kx\ cosec\ (x) = \lim_{x \rightarrow 0}{\ x\ cosec\ (kx)}}$
$\Rightarrow \ \ \ k\lim_{x \rightarrow 0}{\frac{x}{\sin x} =}\lim_{x \rightarrow 0}\frac{x}{\sin{kx}} \times \frac{k}{k}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ k = \frac{1}{k}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ k = \pm 1$