Let $f(2) = 4$ and$f^{'}(2) = 4$. Then, $\lim_{x \rightarrow 2}\frac{xf(2) - 2f(x)}{x - 2}$ is given by

Question

Dr. Abubacker · Accepted Answer

(c)
$\lim_{x ightarrow 2}\frac{xf(2) - 2f(x)}{x - 2}$
$= \lim_{x ightarrow 2}\frac{xf(2) - 2f(2) + 2f(2) - 2f(x)}{x - 2}$
$= f(2) - 2f^{'}(2)$
$= 4 - 2 	imes 4 = - 4$

Q. Let $f(2) = 4$ and$f^{'}(2) = 4$. Then, $\lim_{x \rightarrow 2}\frac{xf(2) - 2f(x)}{x - 2}$ is given by

Explanation

Reviewed by Dr. Abubacker

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