Q. If $f(5) = 7$ and $f^{'}(5) = 7$, then $\lim_{x \rightarrow 5}\frac{xf(5) - 5f(x)}{x - 5}$ is given by

A) 35
B) -35
C) 28
D) -28
Explanation

(d)
$\lim_{x \rightarrow 5}\frac{xf(5) - 5f(x)}{x - 5}$
$= \lim_{x \rightarrow 5}\frac{f(5) - 5f'(x)}{1 - 0} = f(5) - 5f^{'}(5)$
$= 7 - 5.7 = 7 - 35 = - 28$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.