Q. If $\lim_{x \rightarrow a}{\frac{a^{x} - x^{a}}{x^{x} - a^{a}} = - 1}$, then $a$ equal to

A) 1
B) 0
C) $e$
D) $(1/e)$
Explanation

(a)
Given, $\ \lim_{x \rightarrow a}{\frac{a^{x} - x^{a}}{x^{x} - a^{a}} = - 1}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \lim_{x \rightarrow a}\frac{a^{x}\log_{e}a - ax^{a - 1}}{x^{x}(1 + \log_{e}x) - 0} = - 1$ [by L’ Hospital’s rule]
$\Rightarrow \ \ \ \ \ \ \ \ \ {\frac{a^{a}\log_{e}a - a^{a}}{a^{a}(1 + \log_{e}a)} = - 1}$
$\Rightarrow \ \ \ \ \ \ \ \ \ 2\log_{e}{a = 0}\ \ \ \ \ \ \Rightarrow \ \ \ \ \ \ a = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.