Q. Dual of $\left( x^{'} \vee y^{'} \right)^{'} = x \land y$ is
A) $\left( x^{'} \vee y^{'} \right) = x \vee y$
B) $\left( x^{'} \land y^{'} \right)^{'} = x \vee y$
C) $\left( x^{'} \land y^{'} \right)^{'} = x \land y$
D) None of the above
Explanation
(b)
Dual of $\left( x^{'} \vee y^{'} \right)^{'} = x \land y$ is $\left( x^{'} \land y^{'} \right) = x \vee y$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.