Q. $(p \land \sim q) \land (\sim p \land q)$ is
A) a tautology
B) a contradiction
C) tautology and contradiction
D) neither a tautology not a contradiction
Explanation
(b)
[table] $p$ | $q$ | $\sim p$ | $\sim q$ | $p \land \sim q$ | $\sim p \land q$ | $(p \land \sim q)$
$\land$
$(\sim p \land q)$ ; T
T
F
F | T
F
T
F | F
F
T
T | F
T
F
T | F
T
F
F | F
F
T
F | F
F
F
F [/table]
It is clear from, the table that $\ (p \land \sim q) \land (\sim p \land q)$is a contradiction.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.