Q. The false statement in the following is
A) $p \land ( \sim p)$ is a contradiction
B) $(p \Rightarrow q) \Leftrightarrow ( \sim q \Rightarrow \sim p)$ is a contradiction
C) $\sim ( \sim p) \Leftrightarrow p$ is a tautology
D) $p \vee ( \sim p)$ is a tautology
Explanation
(b)
$p \Rightarrow q$ is logically equivalent to $\sim q \Rightarrow \sim p$
$\therefore\ (p \Rightarrow q) \Leftrightarrow ( \sim q \Rightarrow \sim p)$
Is a tautology but not a contradiction
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.