Q. The statement $\sim(p \rightarrow q)$ is equivalent to

A) $p \land (\sim q)$
B) $\sim p \land q$
C) $p \land q$
D) $\sim p \land \sim q$
Explanation

(a)
[table] $p$ | $q$ | $p \rightarrow q$ | $\sim(p \rightarrow q)$ | $\sim q$ | $p \land (\sim q)$ ; T
T
F
F | T
F
T
F | T
F
T
T | F
T
F
F | F
T
F
T | F
T
F
F [/table]
From the table $\sim(p \rightarrow q) \equiv p \land (\sim q)$
$\therefore$ All the values are same.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.