(c)
[table] $q$ | $p$ | $q \rightarrow p$ | $p \rightarrow (q \rightarrow p)$ | $p \vee q$ | $p \rightarrow (p \vee q)$ ; T
T
F
F | T
F
T
F | T
F
T
T | T
T
T
T | T
T
T
F | T
T
T
T [/table]
$\therefore$ Statement $p \rightarrow (q \rightarrow p)$ is equivalent to$\ p \rightarrow (p \vee q)$.