Q. $\sim p \land q$ is logically equivalent to
A) $p \rightarrow q$
B) $q \rightarrow p$
C) $\sim(p \rightarrow q)$
D) $\sim(q \rightarrow p)$
Explanation
(d)
[table] $p$ | $q$ | $\sim p$ | $\sim p \land q$ | $q \rightarrow p$ | $\sim(q \rightarrow p)$ ; T
T
F
F | T
F
T
F | F
F
T
T | F
F
T
F | T
T
F
T | F
F
T
F [/table]
From the table
$\sim p \land q \equiv \sim(q \rightarrow p)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.