Q. $\sim\lbrack p \leftrightarrow q\rbrack$ is
A) Tautology
B) Contradiction
C) neither (a) nor (b)
D) either (a) or (b)
Explanation
(c)
[table] $p$ | $q$ | $p \leftrightarrow q$ | $\sim\lbrack p \leftrightarrow q\rbrack$ ; T
T
F
F | T
F
T
F | T
F
F
T | F
T
T
F [/table]
It is clear from the table that, it is neither tautology nor contradiction.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.