Q. If $p$ and $q$ are statements, then $\sim (p \land q) \vee \sim (q \Leftrightarrow p)$ is
A) Tautology
B) Contradiction
C) Neither tautology nor contradiction
D) Either tautology or contradiction
Explanation
(c)
By the truth table
[table] $p$ | $q$ | $(p \land q)$ | $\sim (p \land q)$ | $q \Leftrightarrow p$ | $\sim (q \Leftrightarrow p)$ | $\sim (p \land q)\ \vee \sim (q \Leftrightarrow p)$ ; T
T
F
F | T
F
T
F | T
F
F
F | F
T
T
T | T
T
F
F | F
F
T
T | F
T
T
T [/table]
It is clear that it is neither tautology nor contradiction
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.