(b) Given $b_{yx} = 0.8,\ b_{xy} = 0.2$ Then, $r = \sqrt{b_{xy}b_{yx} =}\sqrt{(0.8)(0.2)} = \sqrt{0.16}$ $\Rightarrow \ \ \ \ \ r = 0.4$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.