(c)
Let the number of boys and girls be $x\$and$\$y
$\therefore$ $52x + 42y = 50(x + y)$
$\Rightarrow$ $2x = 8y$
$\Rightarrow$ $x = 4y$
$\therefore$ Total number of students in the class
$= x + y = 5y$
$\therefore$ Required percentage of boys
$= \frac{4y}{5y} \times 100\% = 80\%$