(b)
Let $n_{1}and\$ $n_{2}$ be the number of men and women in a group. According to the given condition,
$\frac{n_{1} \times 26 + n_{2} \times 21}{n_{1} + n_{2}} = 25$
$\Rightarrow 26n_{1} + 21n_{2} = 25n_{1} + 25n_{2}$
$\Rightarrow n_{1} = 4n_{2} \Rightarrow \frac{n_{1}}{n_{2}} = \frac{4}{1}$
$\Rightarrow \frac{n_{1}}{{\ n}_{2}} = \frac{80}{20}$