(a) Since, $MD = \frac{4}{5}\sigma,\ \ QD = \frac{2}{3}\sigma$ $\therefore\ \frac{MD}{QD} = \frac{6}{5}$ $\Rightarrow \ \ QD = \frac{5}{6}\ (MD) = \frac{5}{6}(15) = 12.5$
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