Q. Angle between two lines of regression is given by

A) $\tan^{- 1}\left( \frac{b_{xy} - \frac{1}{b_{yx}}}{1 - \frac{b_{xy}}{b_{yx}}} \right)$
B) $\tan^{- 1}\left( \frac{b_{yx}.b_{xy} - 1}{b_{yx}{+ b}_{xy}} \right)$
C) $\tan^{- 1}\left( \frac{b_{xy} - \frac{1}{b_{yx}}}{1 + \frac{b_{xy}}{b_{yx}}} \right)$
D) $\tan^{- 1}\left( \frac{b_{yx} - b_{xy}}{{1 + b}_{yx}{.b}_{xy}} \right)$
Explanation

(b)
The slopes of the lines of regression of $y$ on $x$ and $x$ on $y$ are $m_{1} = b_{yx}\ and\ m_{2} = \frac{1}{b_{xy}}$respectively. Therefore, the angle between them is given by
$tan\theta = \frac{m_{1} - m_{2}}{1 + m_{1}m_{2}} = \frac{b_{yx} - \frac{1}{b_{xy}}}{1 + \frac{b_{yx}}{b_{xy}}}$
$\Rightarrow \theta = \tan^{- 1}\left( \frac{b_{yx} \times b_{xy} - 1}{b_{yx} + b_{xy}} \right)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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