(a) Given, $r = 0.8\ and\ b_{yx} = 0.2$ $\therefore r^{2} = b_{xy}b_{yx}$ $\Rightarrow (0.8)^{2} = b_{xy}.(0.2)$ $\Rightarrow b_{xy} = \frac{0.64}{0.2} = 3.2$
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