Q. The mean-deviation and coefficient of mean deviation from the data. Weight (in kg) 54, 50, 40, 42, 51, 45, 47, 55, 57 is

A) 0.0900
B) 0.0956
C) 0.0056
D) 0.0946
Explanation

(b)
On arranging the terms in increasing order of magnitude
40,42,45,47,50,51,54,55,57
Number of terms ,N=9
$\therefore Median = \left( \frac{9 + 1}{2} \right)th\ term = 5th\ term = 50kg$
[table] Weight (kg) | Deviation from median (d) | |d| ; 40 | -10 | 10 ; 42 | -8 | 8 ; 45 | -5 | 5 ; 47 | -3 | 3 ; 50 | 0 | 0 ; 51 | 1 | 1 ; 54 | 4 | 4 ; 55 | 5 | 5 ; 57 | 7 | 7 ; | | |d|=43 [/table]
MD from median=$\frac{43}{9} = 4.78$kg
$\therefore$Coefficient of MD from median
$= \frac{MD}{median}$
$= \frac{4.78}{50} = 0.0956$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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