Q. Three dice are thrown simultaneously, then probability of throwing a total greater than 4 is
A) $\frac{1}{54}$
B) $\frac{53}{54}$
C) $\frac{5}{108}$
D) None of these
Explanation
(b)
$P$(getting a sum greater than 4)
$= 1 - P($getting a sum less than 5) …(i)
For sum 3, Number of cases=1
For sum 4, Number of cases=3
$\therefore$ Total number of cases=4
From Eq.(i),
$P = 1 - \frac{4}{216} = 1 - \frac{1}{54} = \frac{53}{54}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.