(b)
In a pack of 52 cards, there are 26 black cards.
$\therefore Required\ probability = \frac{\ ^{26}C_{3}}{\ ^{52}C_{3}}$
$= \frac{26 \times 25 \times 24}{3 \times 2 \times 1} \times \frac{3 \times 2 \times 1}{52 \times 51 \times 50}$
$= \frac{2}{17}$