Q. Suppose that a die (with faces marked 1 to 6) is loaded in such a manner that for $K = 1,2,3,\ldots.,$6 the probability of the face marked $K$ turning up when die is tossed is proportional to $K$. The probability of the event that the outcome of a toss of the die will be an even number, is equal to
A) $\frac{1}{2}$
B) $\frac{4}{7}$
C) $\frac{2}{5}$
D) $\frac{1}{21}$
Explanation
(a)
Required probability $= \frac{3}{6} = \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.