The probability distribution of a random variable $X$ is given as [table] $\mathbf{X}$ | $- 5$ | $- 4$ | $- 3$ | $- 2$ | $- 1$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ ; $\mathbf{P(X)}$ | $p$ | $2p$ | $3p$ | $4p$ | $5p$ | $7p$ | $8p$ | $9p$ | $10p$ | $11p$ | $12p$ [/table] Then, the value of $P$ is

Question

Dr. Abubacker · Accepted Answer

(a)
Sum of Probabilities=1
$\Rightarrow \ p + 2p + 3p + 4p + 5p + 7p + 8p + 9p$
$+ 10p + 11p + 12p = 1$
$\Rightarrow \ 72p = 1\  \Rightarrow p = \frac{1}{72}$

Q. The probability distribution of a random variable $X$ is given as [table] $\mathbf{X}$ | $- 5$ | $- 4$ | $- 3$ | $- 2$ | $- 1$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ ; $\mathbf{P(X)}$ | $p$ | $2p$ | $3p$ | $4p$ | $5p$ | $7p$ | $8p$ | $9p$ | $10p$ | $11p$ | $12p$ [/table] Then, the value of $P$ is

Explanation

Reviewed by Dr. Abubacker

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