Q. For a party 8 guests are invited by a husband and his wife. They sit for a dinner around a round table. The probability that the husband and his wife sit together, is
A) $\frac{2}{7}$
B) $\frac{2}{9}$
C) $\frac{1}{9}$
D) $\frac{4}{9}$
Explanation
(b)
Total number of ways of sitting$= 9!$
and number of favourable ways of sitting$= 2 \times 8!$
$\therefore$ Required probability$= \frac{2 \times 8!}{9!} = \frac{2}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.