Q. Two unbiased dice are thrown simultaneously. The probability to get a sum more than 8 is
A) $\frac{5}{36}$
B) $\frac{5}{18}$
C) $\frac{5}{12}$
D) $\frac{2}{9}$
Explanation
(b)
Total number of outcomes=36
Favourable outcomes are (3,6),(4,5),(5,5),(6,5),(6,4),(4,6),(6,3),(5,4),(6,6),(5,6)
Number of favourable outcomes =10
$\therefore$ Required probability$= \frac{10}{36} = \frac{5}{18}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.