Q. Given that $X$ is discrete random variable which takes the values 0,1,2 and $P(X = 0) = \frac{144}{169},\ P(X = 1) = \frac{1}{169},$ then the value of $P(X = 2)$ is
A) $\frac{145}{169}$
B) $\frac{24}{169}$
C) $\frac{2}{169}$
D) $\frac{143}{169}$
Explanation
(b)
Given, $P(X = 0) = \frac{144}{169}\ and\ P(X = 1) = \frac{1}{169}$
$P(X = 2) = 1 - P(X = 1) - P(X = 0)$
$= 1 - \frac{1}{169} - \frac{144}{169} = \frac{169 - 145}{169} = \frac{24}{169}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.