Q. A coin is tossed three times. The probability of getting head and tail alternatively, is
A) $\frac{1}{8}$
B) $\frac{1}{2}$
C) $\frac{1}{4}$
D) None of these
Explanation
(c)
Number of favourable cases $(HTH,HTH) = 2$
Number of total cases $= 2^{3} = 8$
$\therefore$ Required probability $= \frac{2}{8} = \frac{1}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.