Explanation

(d)
In out of 9 tickets, 5 tickets are odd number and 4 tickets are even numbers.
$\therefore$Required probability
$= \left\{ \frac{\ ^{5}C_{1}}{\ ^{9}C_{1}} \times \frac{\ ^{4}C_{1}}{\ ^{8}C_{1}} \times \frac{\ ^{4}C_{1}}{\ ^{7}C_{1}} + \frac{\ ^{4}C_{1}}{\ ^{9}C_{1}} \times \frac{\ ^{5}C_{1}}{\ ^{8}C_{1}} \times \frac{\ ^{3}C_{1}}{\ ^{7}C_{1}} \right\}$
$= \frac{5}{9} \times \frac{4}{8} \times \frac{4}{7} + \frac{4}{9} \times \frac{5}{8} \times \frac{3}{7}$
$= \frac{140}{504} = \frac{5}{18}$