Explanation

(b)
There are two conditions arise.
(i) When first is an ace of heart and second one is non-ace of heart, the probability $= \frac{1}{52} \times \frac{51}{51} = \frac{1}{52}$
(ii) When first is non-ace of heart and second one is an ace of heart, the probability $= \frac{51}{52} \times \frac{1}{51} = \frac{1}{52}$
$\therefore$ Required probability $= \frac{1}{52} + \frac{1}{52} = \frac{1}{26}$