Q. Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is 6?
A) $\frac{5}{36}$
B) $\frac{1}{6}$
C) $\frac{2}{15}$
D) None of these
Explanation
(c)
Favourable cases will be (5,1),(4,2),(2,4),(1,5)
Hence, required probability $= \frac{4}{6.5} = \frac{2}{15}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.