Q. Given two events $A\ and\ B$. If odds against $A$ are 2 : 1 and those in favour of $A \cup B$ are as 3 : 1, then

A) $\frac{1}{2} \leq P(B) \leq \frac{3}{9}$
B) $\frac{5}{12} \leq P(B) \leq \frac{3}{4}$
C) $\frac{1}{2} \leq P(B) \leq \frac{3}{5}$
D) None of these
Explanation

The correct answer is Option B: $\frac{5}{12} \leq P(B) \leq \frac{3}{4}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.