Q. If two dice are thrown together, then the probability that the sum of numbers appearing on them is 9, is
A) $\frac{1}{9}$
B) $\frac{1}{6}$
C) $\frac{1}{4}$
D) $\frac{1}{3}$
Explanation
(a)
Total number of cases $= 6^{2} = 36$
Let $E =$Event of getting sum is 9
$= \{(3,6),\ (6,3),\ (4,5),\ (5,4)\}$
$\therefore\ n(E) = 4$
$\therefore$ Required probability$= \frac{4}{36} = \frac{1}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.