Q. In a binomial distribution, the mean is 4 and variance is 3. Then, its mode is
A) 5
B) 6
C) 4
D) None of these
Explanation
(c)
Given, $np = 4,\ npq = 3V \Rightarrow p = \frac{1}{4},q = \frac{3}{4}$
Mode is an integer $x$ such that
$\Rightarrow \ 4 + \frac{1}{4} > x > 4 - \frac{3}{4}$
${\Rightarrow \ 3.25 < x < 4.25
}{\therefore\ x = 4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.