Q. There are 9999 tickets bearing numbers 0001, 0002,….,9999. If one ticket is selected from these tickets at random, the probability that the number on the ticket will consists of all different digits, is
A) $\frac{5040}{9999}$
B) $\frac{5000}{9999}$
C) $\frac{5030}{9999}$
D) None of these
Explanation
(a)
Total number of cases = 9999
Favourable cases $= 10 \times 9 \times 8 \times 7 = 5040$
$\therefore$ Probability $= \frac{5040}{9999}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.