Q. In shuffling a pack of playing cards, four are accidently dropped. The probability that missing cards should be one from each suit, is
A) $\frac{1}{256}$
B) $\frac{1}{270725}$
C) $\frac{2197}{20825}$
D) None of these
Explanation
(c)
Total cases $= {\ ^{52}C}_{4}$
Favourable cases $= \left( {\ ^{13}C}_{1} \right)^{4}$
So, probability $= \frac{\left( {\ ^{13}C}_{1} \right)^{4}}{{\ ^{52}C}_{4}}$
$= \frac{13 \times 13 \times 13 \times 13 \times 1 \times 2 \times 3 \times 4}{52 \times 51 \times 50 \times 49}$
$= \frac{2197}{20825}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.