Q. A bag contains 4 brown and 5 white balls. A man pulls two balls at random without replacement. The probability that the man gets both the balls of the same colour is
A) $\frac{5}{108}$
B) $\frac{1}{6}$
C) $\frac{5}{18}$
D) $\frac{4}{9}$
Explanation
(d)
$\therefore$ Required probability$= \frac{\ ^{4}C_{2} + \ ^{5}C_{2}}{\ ^{9}C_{2}}$
$= \frac{6 + 10}{36} = \frac{16}{36}$
$= \frac{4}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.