Q. Two dice are thrown $n$ times in succession. The probability of obtaining a double six at least once is
A) $\left( \frac{1}{36} \right)^{n}$
B) ${1 - \left( \frac{35}{36} \right)}^{n}$
C) $\left( \frac{1}{12} \right)^{n}$
D) None of these
Explanation
(b)
$Here,\ p = Probability\ of\ getting\ double\ six\ in\ two\ dice = \frac{1}{6^{2}} = \frac{1}{36}\ and\ q = \frac{35}{36}$
$\therefore Required\ probability = 1 - (Probability\ of\ not\ getting\ double\ six)^{n}$
$= 1 - \left( \frac{35}{36} \right)^{n}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.