Q. 5 boys and 5 girls are sitting in a row randomly. The probability that boys and girls sit alternatively, is
A) $\frac{5}{126}$
B) $\frac{1}{42}$
C) $\frac{4}{126}$
D) $\frac{1}{126}$
Explanation
(d)
Total number of ways in which 5 boys and 5 girls are sitting in a row alternatively $= 2.5!5!$
$\therefore$ Required probability$= \frac{2.5!5!}{10!} = \frac{1}{126}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.