Q. Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house, is
A) $\frac{7}{9}$
B) $\frac{8}{9}$
C) $\frac{1}{9}$
D) $\frac{2}{9}$
Explanation
(c)
Since, all three persons have three options to apply.
$\therefore$ Total cases$= 3^{3}$
Favorable cases=3
$\therefore$ Required probability $= \frac{3}{3^{3}} = \frac{1}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.