Q. If $P(A) = P(B) = P(C) = \frac{1}{4},P(AB) = P(CB) = 0\$and$\ P(AC) = \frac{1}{8}$,then $P(A + B)$is equal to
A) $\frac{5}{8}$
B) $\frac{37}{64}$
C) $\frac{3}{4}$
D) $\frac{1}{2}$
Explanation
(d)
Given, $P(A) = P(B) = P(C) = \frac{1}{4}$
$P(AB) = P(CB) = 0$
and $P(AC) = \frac{1}{8}$
Now, $P(A + B) = P(A) + P(B) - P(AB)$
$= \frac{1}{4} + \frac{1}{4} - 0 = \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.